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I would think it would be 9999 to 1, or 10,000 to 1 if you include 4 zeros

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I'll have a stab

sequence required over 4 numbers can happen only once right? Irrespective of the order or make up - ti will be unique within the 4 digits..

10 * 10 * 10 * 10 (or 10^4) is 10,000

- therefore a 1 in 10,000 probability?

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I think the order is covered in the above examples Tom.All the answers so far are based on the odds of getting that combination of 4 numbers.

However, the 4 numbers have to be in the *right order* as well, so the true odds are even higher.

I can't remember how to work this out, but it's basically very very unlikely indeed.

Ie 1in10 for the first one x 1in10 for the second x 1in10 x 1in10

Adrian

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You're going to have a problem remembering because the answers so far are correct.All the answers so far are based on the odds of getting that combination of 4 numbers.

However, the 4 numbers have to be in the *right order* as well, so the true odds are even higher.

I can't remember how to work this out, but it's basically very very unlikely indeed.

If you

Any maths book reference to 'Permutations' and 'Combinations' will explain.

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Lottery odds are 14 million to one - as you've already had some luck with random numbers (whatever the odds are) I'd say you've got less of a chance in the lottery now.

(That's why I don't buy lucky dips - they're random once, the odds of that sequence happenning again are probably higher)

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Nope, as they are random the chances of the sequence happening again are exactly the same as they were before it hapened the first time.(That's why I don't buy lucky dips - they're random once, the odds of that sequence happenning again are probably higher)

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Quite right, the last draw doesnt affect the next. . .its the same odds to pick 123456 one week as it is the next. I think the name for it (as well as random ) is stochastic...Nope, as they are random the chances of the sequence happening again are exactly the same as they were before it hapened the first time.

Cheers

Adam

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